Explicație pas cu pas:
[tex]{x}^{2} \leqslant 16 \iff \ {x}^{2} \leqslant {4}^{2} \\ \implies 1 \leqslant x \leqslant 4[/tex]
A = {1; 2; 3; 4}
[tex]{x}^{3} \leqslant 64 \iff \ {x}^{3} \leqslant {4}^{3} \\ \implies 1 \leqslant x \leqslant 4[/tex]
B = {1; 2; 3; 4}
=> A = B
A ∪ B = {1; 2; 3; 4}
A ∩ B = {1; 2; 3; 4}
A \ B = Ø
B \A = Ø
