Explicație pas cu pas:
[tex]{( {3}^{4} )}^{7} : {9}^{13} = {3}^{4 \times 7} : { ({3}^{2}) }^{13} = {3}^{28} : {3}^{2 \times 13} = {3}^{28} : {3}^{26} = {3}^{28 - 26} = {3}^{2} = \bf 9 \\ [/tex]
[tex]{( {2}^{9} )}^{2} : {4}^{9} = {2}^{9 \times 2} : {( {2}^{2} )}^{9} = {2}^{18} : {2}^{2 \times 9} = {2}^{18} : {2}^{18} = \bf 1 \\ [/tex]
[tex]{8}^{24} : {16}^{18} = {( {2}^{3} )}^{24} : {( {2}^{4} )}^{18} = {2}^{3 \times 24} : {2}^{4 \times 18} = {2}^{72} : {2}^{72} = \bf 1 \\ [/tex]
[tex]{ \red {125}}^{9} : {25}^{13} = {( {5}^{3} )}^{9} : {( {5}^{2} )}^{13} = {5}^{3 \times 9} : {5}^{2 \times 13} = {5}^{27} : {5}^{26} = {5}^{27 - 26} = {5}^{1} = \bf 5 \\ [/tex]
[tex]{81}^{15} : {27}^{20} = {( {3}^{4} )}^{15} : {( {3}^{3} )}^{20} = {3}^{4 \times 15} : {3}^{3 \times 20} = {3}^{60} : {3}^{60} = \bf 1 \\ [/tex]
[tex]{ {8}^{13} }^{2} = {( {2}^{3} )}^{169} = {2}^{3 \times 169} = \bf {2}^{507} \\ [/tex]
[tex]{ {3}^{7} }^{2} : {81}^{12} = {3}^{49} : {( {3}^{4} )}^{12} = {3}^{49} : {3}^{4 \times 12} = {3}^{49} : {3}^{48} = {3}^{49 - 48} = {3}^{1} = \bf 3 \\ [/tex]
