Răspuns:
a) 0; b) 0
Explicație pas cu pas:
a) n şi p sunt pare:
[tex]x = {( - 1)}^{n + 1} \cdot \frac{1}{2} + {( - 1)}^{n} \cdot \frac{1}{3} + {( - 1)}^{p} \cdot \frac{1}{6} = ( - 1) \cdot \frac{1}{2} + ( + 1) \cdot \frac{1}{3} + ( + 1) \cdot \frac{1}{6} = - \frac{1}{2} + \frac{1}{3} + \frac{1}{6} = \frac{ - 3 + 2 + 1}{6} = \frac{0}{6} = \bf 0[/tex]
b) n şi p sunt impare:
[tex]x = {( - 1)}^{n + 1} \cdot \frac{1}{2} + {( - 1)}^{n} \cdot \frac{1}{3} + {( - 1)}^{p} \cdot \frac{1}{6} = ( + 1) \cdot \frac{1}{2} + ( - 1) \cdot \frac{1}{3} + ( - 1) \cdot \frac{1}{6} = \frac{1}{2} - \frac{1}{3} - \frac{1}{6} = \frac{3 - 2 - 1}{6} = \frac{0}{6} = \bf 0[/tex]
