[tex]\frac{x}{a}=\frac{y}{b}=\frac{z}{c}=2[/tex]
[tex]\frac{x}{a}=\frac{y}{b}=\frac{z}{c}=\frac{x+y+z}{a+b+c}[/tex]
Din cele doua rezulta ca:
[tex]\frac{x+y+z}{a+b+c} =2[/tex]
[tex]2^2-\frac{x+y+z}{a+b+c} =4-2=2[/tex]
x=2a
y=2b
z=2c
[tex]2^4-\frac{x^2+y^2+z^2}{a^2+b^2+c^2} =16-\frac{4a^2+4b^2+4c^2}{a^2+b^2+c^2} =16-\frac{4(a^2+b^2+c^2)}{a^2+b^2+c^2}=16-4=12[/tex]
Alta rezolvare gasesti aici: https://brainly.ro/tema/8888980
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