Răspuns:
c=mdx100/ms---> 10/100=m,d/(md+270)=====>md=300g produs
CH3-CH=CH-CH3+ [O]---> 2CH3COOH (acid acetic)
CH3-CH=CH-CH=CH-CH3+ 8O--> 2CH3COOH+ HOOC-COOH
acid acetic si acid oxalic
HOOC-COOH---> 2CO2+ H2O
miu, acid acetic=60g/mol
niu=m/miu=300/60mol= 5mol
din cele doua ecuatiii, rezulta ca din amestecul echimolar ,din fiecare reactie rezulta 2,5mol acid
deci 1mol 2-butena.......2mol acid acetic
x....................................2,5mol acid
x=niu=1,25mol 2 butena
Explicație: