Explicație pas cu pas:
[tex]( {4}^{31} + 6 \cdot {32}^{12} - 5 \cdot {16}^{15}) \div ( {8}^{21} - 5 \cdot {8}^{20}) - 1= \\ [/tex]
[tex]= \frac{4 \cdot {4}^{30} + 6 \cdot {({2}^{5} )}^{12} - 5 \cdot {( {2}^{4} )}^{15}}{8 \cdot {8}^{20} - 5 \cdot {8}^{20}} - 1 \\ [/tex]
[tex]= \frac{4 \cdot {( {2}^{2} )}^{30} + 6 \cdot {2}^{60} - 5 \cdot {2}^{60}}{3 \cdot {( {2}^{3} )}^{20}} - 1 \\ [/tex]
[tex]= \frac{4 \cdot {2}^{60} + {2}^{60}}{3 \cdot {2}^{60}} - 1 = \frac{5 \cdot {2}^{60}}{3 \cdot {2}^{60}} - 1 \\ [/tex]
[tex]= \frac{5}{3} - 1 = \frac{5 - 3}{3} = \frac{2}{3} \\ [/tex]
