Explicație pas cu pas:
c.
[tex]{5}^{3n + 1} = {25}^{11} \iff {5}^{3n + 1} = {( {5}^{2} )}^{11} \\ {5}^{3n + 1} = {5}^{22} \iff 3n + 1 = 22 \\ 3n = 21 \implies n = 7[/tex]
d.
[tex]{7}^{2n + 1} \div {7}^{4} = {49}^{ {2}^{3} } \iff {7}^{2n + 1 - 4} = {( {7}^{2} )}^{8} \\ {7}^{2n - 3} = {7}^{16} \iff 2n - 3 = 16 \\ 2n = 19 \implies n = \frac{19}{2} [/tex]
e.
[tex]{10}^{2n + 1} \div {5}^{2n + 1} = {8}^{9} \\ {(10 \div 5)}^{2n + 1} = {( {2}^{3} )}^{9} \\ {2}^{2n + 1} = {2}^{27}\iff 2n + 1 = 27 \\ 2n = 26 \implies n = 13[/tex]
