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se considera proporția x-3y/x+3y=1/5 determinati raportul 4x+y/4x-y​

Răspuns :

[tex]\frac{x-3y}{x+3y}=\frac{1}{5} \implies 5(x-3y)=x+3y[/tex]

[tex]\implies 5x-15y=x+3y[/tex]

[tex]\implies 5x-x=3y+15y[/tex]

[tex]\implies 4x=18y[/tex]
Inlocuim pe 4x in raportul care ne intereseaza:

[tex]\frac{4x+y}{4x-y}=\frac{18y+y}{18y-y}=\frac{19y}{17y}=\frac{19}{17}[/tex]