Răspuns:
Explicație pas cu pas:
[tex]3x^{2} -2x-2 > 0[/tex]
[tex]3x^{2} -2x-2=0\\2^{2}-4*3*(-2)=4+24=28[/tex]
[tex]x_{1}=\frac{-(-2)-\sqrt{28} }{6}=\frac{2-2\sqrt{7} }{6}=\frac{1-\sqrt{7} }{3}\\x_{2}=\frac{-(-2)+\sqrt{28} }{6}=\frac{2+2\sqrt{7} }{6}=\frac{1+\sqrt{7} }{3}[/tex]
[tex]x\in(-\infty,\frac{1-\sqrt{7} }{3}) U (\frac{1+\sqrt{7} }{3};+\infty)[/tex]
