Răspuns:
Explicație pas cu pas:
2x/(x^2 +3x) = 2/(x+3)
2/(x^2 +3) = 2/3*( 1/x - 1/(x+3))
∫( 1 -2/(x+3) - 2/3*( 1/x - 1/(x+3)))dx =
x - 2ln(x+3) -2/3*lnx + 2/3*ln(x+3)
Punand limitele :
I = 1 -2ln4 -2/3*ln1 + 2/3*ln4 -(0 -2ln3 -2/3*ln0 + 2/3*ln3)
Dar ln0 = - inf , ceva e gresit la problema!