[tex]x * y=2 x y-x-y+1[/tex]
a)
Inlocuim pe x cu 2 si pe y cu [tex]\frac{1}{2}[/tex] si obtinem:
[tex]2-2-\frac{1}{2} +1=\frac{1}{2}[/tex]
b)
[tex]a * x=2 ax-a-x+1=a\\\\2ax-2a-x+1=0\\\\2a(x-1)-(x-1)=0\\\\(x-1)(2a-1)=0\\\\2a-1=0\\\\a=\frac{1}{2}[/tex]
c)
[tex]f(2 x y-x-y+1)=2(2xy-x-y+1)-1=4xy-2x-2y+1\\\\f(x)\cdot f(y)=(2x-1)(2y-1)=4xy-2x-2y+1[/tex]
Observam ca sunt egale
Un alt exercitiu cu legi de compozitie gasesti aici: https://brainly.ro/tema/9928402
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