Răspuns:
Explicație:
73 kg sol. HCl , c= 50%
react. cu Zn
a. ec
b. g,moli Zn
c. VH2
-se afla md de HCl
md= c . ms : 100
md= 50 . 73 : 100= 36,5 kgHCl
-se afla cantit. de Zn
xkg 36,5kg ykg
Zn + 2HCl = ZnCl2 + H2
65kg 2.36,5kg 2kg
x= 65 . 36,5 : 73= 32,5kg Zn
n= 32,4kg : 65kg/kmoli =0,5kmoli Zn
-se afla VH2
y= 36,5 . 2 : 73= 1kg H
n= 1kg : 2kg/kmol = 0,5 kmoli
VH2= 1kmol .22,4 m³/kmol = 22,4 m³
0 +1 +2 0
Zn + 2HCl= ZnCl2 + H2
0 +2
Zn -2e-----> Zn
+1 0
2H +2e----->2 H
