Răspuns:
A) a<b
Explicație pas cu pas:
a=
[tex] {(2 + {8}^{21} \div {16}^{15} + 6 \times {27}^{10} \div {81}^{7} )}^{7} [/tex]
[tex]a = {(2 + {2}^{63} \div {2}^{60} + 6 \times {3}^{30} \div {3}^{28} )}^{7} [/tex]
[tex]a = {(2 + {2}^{3} + 6 \times {3}^{2}) }^{7 }[/tex]
[tex]a = {(2 + 8 + 6 \times 9)}^{7} [/tex]
[tex]a = {(10 + 54)}^{7} [/tex]
[tex]a = {64}^{7} [/tex]
[tex]b = {( { {2}^{2} }^{5} \div { {2}^{5} }^{2} + 1 ) }^{54} [/tex]
[tex]b = {( {2}^{32} \div {2}^{25} + 1)}^{54} [/tex]
[tex]b = {( {2}^{7} + 1)}^{54} [/tex]
[tex]b = {(128 + 1)}^{54} [/tex]
[tex]b = {129}^{54} [/tex]
a<b
