Explicație pas cu pas:
a)
[tex]{6}^{40} \div {36}^{20} + {480}^{2} \div ({2}^{5} \times 3 \times 5) - 401({3}^{5} \times {2}^{5} \div {6}^{5}) - (352 \div 88)^{3} \\ = {6}^{40} \div {( {6}^{2} )}^{20} + {480}^{2} \div 480 - 401({6}^{5} \div {6}^{5}) - 4^{3} \\ = {6}^{40} \div {6}^{40} + 480 - 401 - 64 = 1 + 15 = 16[/tex]
b)
[tex]\left({3}^{n + 2} + {3}^{n + 3} - 4 \times {3}^{n + 1}\right) \div \left(2 \times {3}^{n + 3} - 5 \times {3}^{n + 2} - {3}^{n}\right) \div 3 \\ = \frac{ \left[ {3}^{n} \left({3}^{2} + {3}^{3} - 4 \times 3\right) \right]}{3 \times {3}^{n} \left(2 \times {3}^{3} - 5 \times {3}^{2} - 1\right) } \\ = \frac{ {3}^{n} \left(9 + 27 - 12 \right)}{3 \times {3}^{n} \left(54 - 45 - 1\right)} = \frac{24}{3 \times 8} = 1 [/tex]
