[tex]H_{2} CO_{3} - > M_{H_{2}CO_{3} } =[/tex](2x1)+(1x12)+(3x16)=2+12+48=62 u.a.m (acid carbonic)
[tex]A_{H} =1A_{C} =12A_{O} =16[/tex]
Explicație:
HCl->[tex]M_{HCl}[/tex]=(1x1)+(1x35,5)=1+35,5=36,5 u.a.m (Acid clorhidric)
[tex]A_{H} =1A_{Cl} =35,5[/tex]
[tex]N[/tex][tex]H_{3}[/tex]->[tex]M_{NH_{3} } =[/tex](1x14)+(3x1)=14+3=17 u.a.m (Amoniac)
[tex]A_{N} =14A_{H} =1[/tex]
[tex]CH_{4}- > M_{CH_{4} } =[/tex](1x12)+(4x1)=12+4=16 u.a.m (Metan)
[tex]A_{C} =12A_{H} =1[/tex]
[tex]CO_{2} - > M_{CO_{2} } =[/tex] (1x12)+(2x16)=12+32=44 u.a.m (Dioxid de carbon)
[tex]A_{C}= 12A_{O} = 16[/tex]
[tex]H_{2} O- > M_{H_{2}O } =[/tex](2x1)+(1x16)=2+16=18 u.a.m (apa)
[tex]A_{H} =1A_{O} =16[/tex]
[tex]SO_{2} - > M_{SO_{2} }=[/tex] (1x32)+(2x16)=32+32=64 u.a.m (dioxid de sulf)
[tex]A_{S} =32A_{O} =16[/tex]
[tex]SO_{3} - > M_{SO_{3} } =[/tex](1x32)+(3x16)=32+48=80 u.a.m (trioxid de sulf)
[tex]A_{S} =32A_{O} =16[/tex]
[tex]H_{2} SO_{4} - > M_{H_{2} SO_{4} } =[/tex](2x1)+(1x32)+(16x4)=2+32+64=98 u.a.m (acid sulfuric)
[tex]A_{H} =1A_{S} =32A_{O} =16[/tex]
[tex]CuSO_{4} - > M_{CuSO_{4} } =[/tex](1x64)+(1x32)+(4x16)=64+32+64=160 u.a.m (sulfat de cupru)
[tex]A_{Cu} =64A_{S} =32A_{O} =16[/tex]
