Explicație pas cu pas:
[tex]h = \frac{l \sqrt{3} }{2} = > l = \frac{2h}{ \sqrt{3} } = \frac{2h \sqrt{3} }{3} [/tex]
[tex]a)h = \frac{2 \sqrt{3} \times 14 \sqrt{3}}{3} = > 28 \: cm[/tex]
[tex]b)h = \frac{2 \sqrt{3} ×6}{3} = 4 \sqrt{3} \: cm [/tex]
[tex]c)h = \frac{2\sqrt{3}\times 18 \sqrt{2}}{3} =12 \sqrt{6} [/tex]
[tex]d)h = \frac{2 \sqrt{3} \times 15 \sqrt{6} }{3} = 30 \sqrt{3} \: cm[/tex]
