determinati numarul natural N pentru inegalitatea

Explicație pas cu pas:
[tex]- \frac{81^{6} }{ {9}^{n} \div 3} < - \frac{ {27}^{8} }{ {3}^{n} \times 9} \\ - \frac{( {3}^{4})^{6} }{ { ({3}^{2}) }^{n} \div 3} < - \frac{ ({{3}^{3}})^{8} }{ {3}^{n} \times {3}^{2} } \\- \frac{{3}^{24} }{ {{3}^{2n - 1} }} < - \frac{ {{3}^{24}}}{ {3}^{n + 2}} \\- {3}^{24 - 2n + 1} < - {3}^{24 - n - 2} \\ {3}^{25 - 2n} > {3}^{22 - n} \\ 25 - 2n > 22 - n = > n < 3[/tex]
n ∈ N => n ∈ {0; 1; 2}