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ctg x = 4/3
tg2x = ?
x apartine cadranului III


Răspuns :

Avem urmatoarea formula a tangentei unghiului dublu:

[tex]tg2x=\frac{2tgx}{1-tg^2x}[/tex]

Stim ca:

[tex]ctgx=\frac{1}{tgx}[/tex]

[tex]tgx=\frac{3}{4}[/tex]

[tex]tg2x=\frac{2\times \frac{3}{4} }{1-(\frac{3}{4})^2 }\\\\tg2x=\frac{\frac{3}{2} }{1-\frac{9}{16} } =\frac{3}{2}\times \frac{16}{7} =\frac{24}{7}[/tex]