a) 5×{4×[3×(2×x+1)+1]+1}-44=876
5×{4×[3×(2x+1)+1]+1}=876+44
5×{4×[3×(2x+1)+1]+1}=920
4×[3×(2x+1)+1]+1=920:5
4×[3×(2x+1)+1]+1=184
4×[3×(2x+1)+1]=184-1
4×[3×(2x+1)+1]=183
3×(2x+1)+1=183:4
3×(2x+1)+1=45,75
3×(2x+1)=45,75-1
3×(2x+1)=44,75
2x+1=44,75:3
2x+1=14,91
2x=14,91-1
2x=13,91
x=13,91:2
x=6,955
b)
[tex] \frac{x - 1}{4} + 1 = x - \frac{x - 3}{2} + 0.25 \\ \frac{x - 1}{4} + \frac{1}{1} = \frac{x}{1} - \frac{x - 3}{2} + \frac{25}{10} \\ \frac{5x - 5}{20} + \frac{20}{20} = \frac{20x}{20} - \frac{10x - 30}{20} + \frac{50}{20} \\ (5x - 5 )+ 20 = 20x - (10x - 30 ) + 50 \\ 5x - 5 + 20 = 20x - 10x + 30 + 50 \\ 5x - 20x + 10x = 30 + 50 - 20 \\ - 5x = 60 \\ x = 60 \div ( - 5) \\ x = - 12[/tex]
c)
[tex] \frac{1}{ \sqrt{3} } \times (x - 2) + \sqrt{48} = \sqrt{12} \\ \frac{ \sqrt{3} }{3} \times (x - 2) + 4 \sqrt{3} = 2 \sqrt{3} \\ \frac{ \sqrt{3} }{3} \times \frac{3x - 6}{3} + \frac{12 \sqrt{3} }{3} = \frac{6 \sqrt{3} }{3} \\ \sqrt{3} \times (3x - 6) + 12 \sqrt{3} = 6 \sqrt{3} \\ \sqrt{3} \times (3x - 6) = 6 \sqrt{3} - 12 \sqrt{3} \\ \sqrt{3} \times (3x - 6) = - 6 \sqrt{3} \\ 3x - 6 = - 6 \sqrt{3} \div \sqrt{3} \\ 3x - 6 = - 6 \\ 3x = - 6 + 6 \\ 3x = 0 \\ x = 0 \div 3 \\ x = 0[/tex]
d) nu exista ecuatii echivalente
