[tex]\it \mathcal{P}=AB+BC+AC = 536\ \ \ \ (1)\\ \\ AB=AC;\ \ \ \ BC=\dfrac{5}{3}AB \ \ \ \ (2)\\ \\ (1),\ (2) \Rightarrow AB+\dfrac{2}{3}AB+AB=536|_{\cdot3} \Rightarrow 3AB+2AB+3AB=3\cdot536 \Rightarrow \\ \\ \Rightarrow 8AB=3\cdot536|_{:8} \Rightarrow AB=3\cdot67 \Rightarrow AB=201\ cm\\ \\ BC=\dfrac{2}{3}\cdot201=2\cdot67=134\ cm\\ \\ \\ A\d sadar, \ lungimile\ cerute\ sunt:\ AB=AC=201\ cm,\ \ BC=134\ cm[/tex]
