Explicație pas cu pas:
[tex]\bf{ (\frac{4}{9} ) {}^{12} \div ( \frac{8}{27} ) {}^{8} + ( \frac{9}{25} ) {}^{15} \div ( \frac{27}{125} ) {}^{10} } = \\ [/tex]
[tex]\bf{ = ( \frac{2}{3}) {}^{24} \div ( \frac{2}{3} ) {}^{24} + ( \frac{3}{5}) {}^{30} \div ( \frac{3}{5} ) {}^{30} } \\ [/tex]
[tex]\bf{ = 1 + 1 = \underline\pink{{2}} }[/tex]
