ajutati maaaa ex 8.......

BM=18
MC=32
BC=18+32=50
Aplicam teorema inaltimii in BOC dr in O
OM²=BM×MC
OM=√18×32
OM=√576=24cm
[tex]A_{BOC}=\frac{OM\times BC}{2}=\frac{24\times 50}{2}=600cm^2[/tex]
[tex]A_{ABCD}=4\times A_{BOC}=2400cm^2[/tex]