Răspuns:
[tex]18.066 \times 10 ^{23} at \: \: fe..........x \: \: \: moli \\ \\ 6.022 \times 10^{23} at \: \: fe.........1 \: \: mol[/tex]
[tex]x = \frac{6.022 \times {10}^{23} }{18.066 \times 10^{23} } = \frac{1}{3} \: \: moli \: \: fier \\ \\ [/tex]
16/3 moli amestec...1/3 moli Fier...5moli Cupru
100.............................x % Fier .........y % Cupru
[tex]x = \frac{100 \times \frac{1}{3} }{ \frac{16}{3} } = \\ \\ = \frac{100 \times 3 \times \frac{1}{3} }{16} = \\ \\ = \frac{100}{16} = \\ \\ = 6.25\%[/tex]
[tex]y = \frac{100 \times 5}{ \frac{16}{3} } = \\ \\ = \frac{100 \times 5 \times 3}{16} = \\ \\ = \frac{1500}{16} = \\ \\ = 93.75\%[/tex]
Daca adunam cele doua procente, ne da fix 100%.
Succes! ♡︎♥︎♡︎
