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abc ab =3 cm bc =5 cm qc =4 cm be bis a unghiului b ae=?​

Răspuns :

ΔABC dr in A

Reciproca teoremei lui Pitagora

5²=3²+4²

25=9+16

25=25

Teorema bisectoarei

[tex]\frac{AB}{AE} =\frac{BC}{EC} \\\\\frac{3}{AE} =\frac{5}{EC} =k\\\\AE=\frac{k}{3} \\\\EC=\frac{k}{5}[/tex]

[tex]AE+EC=AC=4[/tex]

[tex]\frac{k}{3}+\frac{k}{5}=4[/tex]

5k+3k=60

8k=60

[tex]k=\frac{15}{2} \\\\AE=\frac{15}{2}\times \frac{1}{3} =2,5\\\\[/tex]