Răspuns: [tex]\bf \red{\bf ~\dfrac{29}{25}}[/tex]
Explicație pas cu pas:
[tex]\bf \bigg(\dfrac{2}{5} \bigg)^0+\bigg(\dfrac{2}{5} \bigg)^{17}:\Bigg[\bigg(\dfrac{2}{5} \bigg)^3\Bigg]^5= \bigg(\dfrac{2}{5} \bigg)^0+\bigg(\dfrac{2}{5} \bigg)^{17}:\bigg(\dfrac{2}{5} \bigg)^{3\cdot5}=[/tex]
[tex]\bf 1+\bigg(\dfrac{2}{5} \bigg)^{17}:\bigg(\dfrac{2}{5} \bigg)^{15}= 1+\bigg(\dfrac{2}{5} \bigg)^{17-15}=[/tex]
[tex]\bf 1+\bigg(\dfrac{2}{5} \bigg)^{2}=1+\dfrac{2^2}{5^2} =\dfrac{^{25)}1~}{1}+\dfrac{4}{25}=[/tex]
[tex]\bf \dfrac{25}{25}+\dfrac{4}{25}=\red{ \boxed{\bf ~\dfrac{29}{25}}}[/tex]
==pav38==
