5
13
a decât
14
5 74
17
2
2
b
OT
3
89
Repede va rog!!!

Răspuns: [tex]\green{\bf~\dfrac{8}{27} ~}[/tex]
Explicație pas cu pas:
[tex]\bf \Bigg[\bigg(\dfrac{2}{3} \bigg)^5\Bigg]^4:\bigg(\dfrac{2}{3} \bigg)^{17}=\bigg(\dfrac{2}{3} \bigg)^{5\cdot4}:\bigg(\dfrac{2}{3} \bigg)^{17}=[/tex]
[tex]\bf \bigg(\dfrac{2}{3} \bigg)^{20}:\bigg(\dfrac{2}{3} \bigg)^{17}=\bigg(\dfrac{2}{3} \bigg)^{20-17}=\bigg(\dfrac{2}{3} \bigg)^{3}=[/tex]
[tex]\bf \dfrac{2^3}{3^3} =\green{\boxed{\bf~\dfrac{8}{27} ~}}[/tex]
[tex]\red{\bf \underline{Formule~pentru~puteri}:}[/tex]
[tex]\bf a^{0} = 1;[/tex]
[tex]\bf (a^{n})^{m} = a^{n \cdot m};[/tex]
[tex]\bf a^{n}\cdot a^{m} =a^{n+m};[/tex]
[tex]\bf a^{n}: a^{m} =a^{n-m}[/tex]
==pav38==