Nu am înțeles punctul i, vă rog ajutați-mă

Răspuns:
/= supra ^=putere
i) 2 intregi 1/3 ^36÷49/9^17
2intregi 1/3=7/3
7 /3^36÷(49/9)^17
49/9=(7/3)^2
[7/2)^2)^17= (7/3)14
(7/3)^36÷(7/3)^34
(7/3)^36÷(7/3)^34=7/3 ^36-34
(7/3)^36-34=(7/3)^2
(7/3)^2=7^2/3^2
7^2/3/2=49/9