Răspuns:
2)
[tex]2 \frac{5}{6} - 2 \frac{2}{9} \div 4 \frac{1}{6} = [/tex]
[tex] \frac{2 \times 6 + 5}{6} - \frac{2 \times 9 + 2}{9} \div \frac{4 \times 6 + 1}{6} = [/tex]
[tex] ^{6)} \frac{17}{6} - ^{4)} \frac{20}{9} \div \frac{25}{6} = [/tex]
[tex] \frac{17}{6} - \frac{4}{3} \times \frac{2}{5} = [/tex]
[tex] \frac{17}{6} - \frac{8}{15} = [/tex]
[tex] \frac{23}{10} [/tex]
3)
[tex] \frac{27}{25} \div 1 \frac{5}{49} - \frac{36}{35} \div 2 \frac{6}{7} = [/tex]
[tex] \frac{27}{25} \div \frac{1 \times 49 + 5}{49} - \frac{36}{35} \div \frac{2 \times 7 + 6}{7} = [/tex]
[tex] \frac{27}{25} \div \frac{54}{49} - \frac{36}{35} \div \frac{20}{7} = [/tex]
[tex] \frac{27}{25} \times \frac{49}{54} - \frac{36}{35} \times \frac{7}{20} = [/tex]
[tex] \frac{1}{25} \times \frac{49}{2} - \frac{9}{5} \times \frac{1}{5} = [/tex]
[tex] \frac{49}{50} - ^{2)} \frac{9}{25} = [/tex]
[tex] \frac{49}{50} - \frac{18}{50} = [/tex]
[tex] \frac{31}{50} [/tex]
[tex]inversul \: sau \: = \frac{50}{31} [/tex]
