[tex]1 \ \frac{1}{3} + \frac{12}{23} \times { \frac{1}{3} + 1 \div ( \frac{1}{7} + \frac{1}{2} \div 3 \ \frac{1}{2} ) } = 1 \ \frac{1}{3} + \frac{12}{23} \times ( \frac{1}{3} + 1 \div \frac{2}{7} ) = 1 \ \frac{1}{3} + \frac{12}{23} \times \frac{23}{6} = 1 \frac{1}{3} + 2 = 3 \frac{1}{3} = \frac{10}{3} \\ \\ 80 \times { \frac{1}{40} + \frac{1}{83} ( \frac{1}{120} - \frac{7}{240} - 1 \frac{1}{60} ) } = 80 \times | \frac{1}{40} + \frac{1}{83} \times ( - \frac{83}{80} ) | = 80 \times ( \frac{1}{40} - \frac{18}{80} ) = 80 \times \frac{1}{80} = 1[/tex]
ultima ecuatie am scris-o în modul deoarece nu am găsit parantezele pătrate
succea!!
