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amplificati prin 3 urmatoarele fractii: a) 3x-1/2x-3 b)x/2x+1. c)2x+3/7x-5
dau coroanaaa
va roog​


Răspuns :

³ [tex]\frac{3x-1}{2x-3} = \frac{9x-3}{6x-9}[/tex]

³[tex]\frac{x}{2x+1} = \frac{3x}{6x+3}[/tex]

³[tex]\frac{2x+3}{7x-5} = \frac{6x+9}{21x-15}[/tex]