cine ma poate ajuta ?
dau coroana

Răspuns:
l b. f°g=f(g(x))=[g(x)]^3=((x^6)^3=x^18
g°f=((x^3)^6=x^18
a. f(g(-1))=(-1)^18=1=g(f(-1))
f(g(x^2/3))=(x^2/3)^18=x^12
g(f(-3^1/3))=(-3^1/3)^18=3^6