Răspuns:
[tex]a) \frac{1}{18} + \frac{1}{9} + \frac{1}{6} = \frac{1 + 2 + 3}{18} = \frac{ {6}^{(6} }{ {18}^{(6} } = \frac{1}{3} \\ \\ b) \frac{7}{36} - \frac{1}{18} + \frac{3}{4} = \frac{7 - 2 + 27}{36} = \frac{ {32}^{(4} }{ {36}^{(4} } = \frac{8}{9} [/tex]
sper că te-am ajutat
