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X-1 + 3x+2
—- ———
X+1. X+1


Răspuns :

[tex]\displaystyle{ \frac{x-1}{x+1}+ \frac{3x + 2}{ x+1}=\frac{x-1+3x+2}{x+1} }[/tex]

[tex]\displaystyle{ =\frac{4x+1}{x+1} }[/tex]

[tex]\it \dfrac{x-1}{x+1}+\dfrac{3x+2}{x+1}=\dfrac{x-1+3x+2}{x+1}=\dfrac{4x+1}{x+1}[/tex]