[tex]\it x^2=4-2\sqrt3=3+1-2\sqrt3=(\sqrt3)^2-2\sqrt3+1^2=(\sqrt3-1)^2\\ \\ Prin\ urmare,\ ecua\c{\it t}ia\ devine:\\ \\ x^2=(\sqrt3-1)^2 \Rightarrow \sqrt{x^2}=\sqrt{(\sqrt3-1)^2} \Rightarrow |x|=|\sqrt3-1| \Rightarrow x=\pm(\sqrt3-1)\\ \\ S=\{-\sqrt3+1,\ \ \sqrt3-1\}[/tex]
