va rog cât mai repede dau coroana

Răspuns:
Explicație pas cu pas:
un indiciu : pentru a calcula mai usor trebuie sa introduci intregii in fractie.
"/" - fractie
a) = 29/6 + 10/3 = (29+20)/6 = 49/6
b) = 9/4 + 19/6 = (27+38)/12 = 65/12
c) = 22/5 + 13/4 = (88+65)/20 = 153/20
d) = 21/4 + 19/8 = (42+19)/8 = 61/8
Răspuns: Ai mai jos rezolvarea
Explicație pas cu pas:
[tex]\bf a)~~4\dfrac{5}{6}+2\dfrac{4}{3}=\dfrac{4\cdot6+5}{6}+ \dfrac{2\cdot3+4}{3}=[/tex]
[tex]\bf\dfrac{29}{6}+ \dfrac{^{2)}10~}{3}=\dfrac{29+20}{6}=\red{\boxed{\bf \dfrac{49}{6}}}[/tex]
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[tex]\bf b)~~2\dfrac{1}{4}+3\dfrac{1}{6}=\dfrac{2\cdot4+1}{4}+ \dfrac{3\cdot6+1}{6}=[/tex]
[tex]\bf\dfrac{^{3)}9~}{4}+ \dfrac{^{2)}19~}{6}=\dfrac{27+38}{12}=\purple{\boxed{\bf \dfrac{65}{12}}}[/tex]
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[tex]\bf c)~~4\dfrac{2}{5}+3\dfrac{1}{4}=\dfrac{4\cdot5+2}{5}+ \dfrac{3\cdot4+1}{4}=[/tex]
[tex]\bf\dfrac{^{4)}22~}{5}+ \dfrac{^{5)}13~}{4}=\dfrac{88+65}{20}=\blue{\boxed{\bf \dfrac{153}{20}}}[/tex]
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[tex]\bf d)~~5\dfrac{1}{4}+2\dfrac{3}{8}=\dfrac{5\cdot4+1}{4}+ \dfrac{2\cdot8+3}{8}=[/tex]
[tex]\bf\dfrac{^{2)}21~}{4}+ \dfrac{19}{8}=\dfrac{42+19}{8}=\green{\boxed{\bf \dfrac{61}{8}}}[/tex]
==pav38==