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Fie multimea M = {0/3,1/3,2/3,3/3,4/3,5/3,6/3} repede dau coroana
aflati: a) M∩N b) M∩N c) M\N


Răspuns :

[tex]\it M=\Big\{\dfrac{0}{3},\ \ \dfrac{1}{3},\ \ \dfrac{2}{3},\ \ \dfrac{3}{3},\ \ \dfrac{4}{3},\ \ \dfrac{5}{3},\ \ \dfrac{6}{3}\Big\}=\Big\{0,\ \ \dfrac{1}{3},\ \ \dfrac{2}{3},\ \ 1,\ \ \dfrac{4}{3},\ \ \dfrac{5}{3},\ \ 2\Big\}\\ \\ \\ M\cap\mathbb{N}=\{0,\ \ 1,\ \ 2\}\\ \\ \\ M\setminus\mathbb{N} =\Big\{\dfrac{1}{3},\ \ \dfrac{2}{3},\ \ \dfrac{4}{3},\ \ \dfrac{5}{3}\Big\}[/tex]