Explicație pas cu pas:
A={x apartine R | -3 < 1-2x < 11}
-3 < 1-2x < 11 /-1
-4 < -2x < 10 /:(-2)
2 > x > -5 => x aparține (-5 , 2)
A intersectat N = { -4,-3,-2,-1,0,1 }
B={x apartine R | 1/2 <(=) x+2/6 <(=) 5/3}
[tex] \frac{1}{2} \leqslant \frac{x + 2}{6} \leqslant \frac{5}{3} \\ 3 \leqslant x + 2 \leqslant 10 \\ 1 \leqslant x \leqslant 8 [/tex]
=> x apartine [1,8]
A intersectat B = [1,2)
