Explicație:
- Ex. 5: Mezii sunt egali cu extremii (Adica diagonalele se inmultesc intre ele)
a) [tex]\frac{x}{16}=\frac{4}{x}[/tex] => [tex]x*x = 16 *4[/tex] => [tex]x^{2} = 64 => x=\sqrt{64}=>x=8[/tex]
b) [tex]\frac{4}{x} =\frac{x}{9} => x^{2} =36=>x=6[/tex]
c) [tex]\frac{x}{5} = \frac{3}{x} => x^{2} = 15 => x=3,87[/tex]
d) [tex]\frac{2,5}{x}=\frac{x}{8} => x^{2} =20=>x=4,47[/tex]
e) [tex]x^{2} = 2\sqrt{225}=>x^{2} =30 =>x=5,47[/tex]
f)[tex]\frac{x}{2\frac{3}{4} }= \frac{11}{x} =>\frac{x}{ 2,75} =\frac{11}{x} => x^{2} =30.25=> x=5.5[/tex]
- Ex. 6: Media geometrica al numerelor x si y este egala cu [tex]\sqrt{x*y}[/tex]
a) [tex]\sqrt{12*3}=\sqrt{36}=6[/tex]
b) [tex]\sqrt{16} =[/tex] 7.74
c) [tex]\sqrt{144}=12[/tex]
d) [tex]\sqrt{3\frac{1}{5}*5}=\sqrt{\frac{16}{5}*5}=\sqrt{16} = 7.74[/tex]
e) [tex]\sqrt{\frac{7}{12}*2\frac{1}{3}}=\sqrt{\frac{7}{12}*\frac{7}{3}}=\sqrt{0.58*2,(3)} = \sqrt{3,48} =1,86[/tex]
f) [tex]\sqrt{\sqrt{5}^{-1}*\sqrt{\frac{5}{16}}} = \sqrt{\sqrt{5^{-1}*\frac{5}{16}}}=\sqrt[4]{5^{-1}*\frac{5}{16}}=\sqrt[4]{\frac{1}{16}}=5[/tex]
Sper ca te-am ajutat!
