Răspuns:
1. 2(1+2+3+...+40) :(1+2+3+...+40) = 2 x1= 2
2. daca a+b= 7 avem variantele : 1+6=7, 2+5=7, 3+4=7 , 4+3=7 , 5+2=7, 6+1=7
adica a= { 1, 2,3, 4, 5, 6} b={ 6, 5, 4,3,2,1}
ab+ba= 16+61=77 25+52=77 34+43= 77
ab+ba= 77
4. 3c + 2 p= 16 lei 2c+3p= 19 lei le scadem si obtinem 1c +1 p= 3 lei
6. a= [tex]3^{15+31}[/tex] = [tex]3^{46}[/tex] b= [tex](3^{2})^{27}[/tex]: [tex]3^{7}[/tex]= [tex]3^{54-7}[/tex]= [tex]3^{47}[/tex] c= [tex](3^{17} )^{3}[/tex]= [tex]3^{17x3}[/tex]= [tex]3^{51}[/tex]
ordinea este a , b, c
