Explicație pas cu pas:
[tex] \frac{12}{ \sqrt{6}- \sqrt{2} } [/tex] =[tex] \frac{12( \sqrt{6} + \sqrt{2}) }{6 - 2} = \frac{12( \sqrt{6} + \sqrt{2} ) }{4} = 3( \sqrt{6} + \sqrt{2} ) = 3 \sqrt{6} + 3 \sqrt{2} [/tex]
[tex] \frac{4}{ \sqrt{7}- \sqrt{5} } [/tex] = [tex] \frac{4( \sqrt{7} + \sqrt{5} ) }{2} = 2( \sqrt{7} + \sqrt{5} ) = 2 \sqrt{7} + \sqrt{5} [/tex]
[tex] \frac{8}{ \sqrt{6} + \sqrt{2} } [/tex] =[tex] \frac{8( \sqrt{6} - \sqrt{2}) }{4} = 2( \sqrt{6} - \sqrt{2} ) = 2 \sqrt{6} - 2 \sqrt{2} [/tex]
[tex] \frac{6}{ \sqrt{5}- \sqrt{2} } [/tex] =[tex] \frac{6( \sqrt{5} - \sqrt{2}) }{3 } = 2 \sqrt{5} - 2\sqrt{2} [/tex]
