Salut!
Ai mai jos rezolvarea in C++
#include <iostream>
#include <fstream>
using namespace std;
ifstream fin("date.in");
int main()
{
int a[1000], n;
bool ok = true;
fin >> n;
for (int i = 0; i < n; ++i)
{
fin >> a[i];
}
for (int i = 0, j = n - 1; i < n, j >= 0; ++i, --j)
{
if (a[i] != a[j])
{
ok = false;
}
}
if (ok)
{
cout << "DA";
}
else
{
cout << "NU";
}
return 0;
}
