Răspuns:
Explicație pas cu pas:
Din prima matrice =>
2a+b = 1
a+b-c-d = 0 => a+b = c+d
a+b+d+2c = 0
2b-a = 1 => a = 2b-1 =>
2(2b-1)+b = 1 ; 4b-2+b = 1 =>
5b = 3 => b = 3/5
a = 6/5 - 1 = > a = 1/5
a+b = c+d = 1/5 + 3/5 = 4/5
4/5 + 4/5 + c = 0 => c = -8/5
d = 4/5 + 8/5 = > d = 12/5
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Din a doua matrice =>
c-d+a+x = 0 => a+x = d-c => x = d-c-c-d = -2c
c+y = 0 => c = -y
d+z = 0 => d = -z
c+d-a = 0 => a = c+d
daca c = -8/5 => y = 8/5
x = -2c = > x = 16/5 ;
daca a = 1/5 => d = 9/5 => z = -9/5
